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A block rests on a rough horizontal surface (μ s = 0.5, μ k = 0.4). A constant horizontal force, just sufficient to start the block in motion, is applied. The acceleration of the block, in m/s 2, is: a. 0. b. 0.98. c. 3.3. d. 4.5. e. 8.9 . Ans. B . 6. An object moves in a circle at constant speed. The work done by the centripetal force is ...

49. Two blocks X and Y are in contact on a horizontal frictionless surface. A 36 N constant force is applied to X as shown to the right. The force exerted by X on Y is: (A) 1.5 N (B) 6.0 N (C) 29 N (D) 30 N (E) 36 N 50. Assume the objects in the following diagrams have equal mass and the strings holding them in place are identical.
constant horizontal force of 45 N is applied to the crate, and it remains at rest. 45 N What is the magnitude of the force of static friction acting on the crate? The acceleration due to gravity is 10 m/s 2. 1. 45 N correct 2. f s is undefined in such a case.
Nov 02, 2016 · Since the crate is moving at constant velocity the net force on the crate is zero. The frictional force due to the surface is given by: #sf(F=muR)# Since the crate is moving we are referring to the coefficient of dynamic friction. #sf(R)# is the reaction and is equal to the weight of the block mg. #:.# #sf(R=mg=25xx9.8=245color(white)(x)N)#
Created Date: 4/28/2008 5:09:46 PM
A curve in a road forms part of a horizontal circle. As a car goes around it at constant speed 14.0 m/s, the horizontal total force on the driver has magnitude 149 N. What is the total horizontal force on the driver if the speed on the same curve is 23.9 m/s instead? Let’s call F 1 and F 2 the forces exerted at speed v 1 and speed v 2 ...
22. Two forces are applied to a 2.0-kilogram block on a frictionless horizontal surface, as shown in the diagram below. The acceleration of the block is 2.5 m/s 2 to the left 23. A 50.-Newton horizontal force is needed to keep an object weighing 500. Newtons moving at a constant velocity of 2.0 meters per second across a horizontal surface.
7.6 A 15.0-kg block is dragges over a rough, horizontal surface by a 70.0-N force acting at 20 o above the horizontal. The block is displaced 5.0 m and the coefficient of kinetic friction is 0.30. Find the work done by (a) the 70-N force, (b) the normal force, and (c) the force of gravity. (d) What is the energy loss due to friction? W = F d cos
The coefficient of static friction between the box and the surface is 0.30. A horizontal 140-N force is applied to the box. What is the friction force on the box? A) 140 N. B) 160 N. C) 16.5 N. D) 0.00 N. E) 42 N. Answer: A. Var: 1 70) A horizontal 52-N force is needed to slide a box across a flat surface at a constant velocity of 3.5 m/s.
Friction-Force Worksheet/Problems (1) A horizontal force of 400.0 N is required to pull a 1760 N trunk across the floor at constant speed. Find the coefficient of sliding friction. (2) How much force must be applied to push a 1.35 kg. book across the desk at constant speed if the coefficient of sliding friction is 0.30?
A constant 20.0-N horizontal force is applied to the object causing the spring to stretch. (a) Determine the speed of the block after it has moved 0.30 m from equilibrium if the surface between the block and the tabletop is frictionless.
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  • If an object of constant mass experiences a constant net force, it will have a constant the object accelerates in the direction of the applied force. If more horizontal force is applied to a sliding object than is needed to maintain a constant velocity,
  • A constant horizontal force F is applied to a lawn roller in the form of a uniform solid cylinder of radius R and mass M (Fig. P10.78). If the roller rolls without slipping on the horizontal surface, show that (a) The acceleration of the center of mass is 2F/3M and (b) The minimum coefficient of friction necessary to prevent slipping is F/3Mg.
  • A 3.0-kg block slides on a rough horizontal surface. A force of 8.0 N acting parallel to the surface is applied to the block. The coefficient of kinetic friction between the block and the surface is 0.15. What is the magnitude of the block's acceleration? 1) 1.9 m/s2 2) 1.2 m/s2 3) 2.3 m/s2 4) 1.5 m/s2 5) 2.9 m/s2 Answer: 2
  • A block of mass m rests on a horizontal floor with which it has a coefficient of static friction μ. It is desired to make the body move by applying the minimum possible force F. Find the magnitude of F and the direction in which it has to be applied.
  • A 3.0-kg block slides on a rough horizontal surface. A force of 8.0 N acting parallel to the surface is applied to the block. The coefficient of kinetic friction between the block and the surface is 0.15. What is the magnitude of the block's acceleration? 1) 1.9 m/s2 2) 1.2 m/s2 3) 2.3 m/s2 4) 1.5 m/s2 5) 2.9 m/s2 Answer: 2

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A 3.80 kg block is pushed along the ceiling with a constant. applied force of 85.0 N that acts at an angle of 55.0� with the. horizontal, as in the figure below. The block accelerates to the. right at 6.00 m/s2. Determine the coefficient of kinetic. friction between block and ceiling.
7.6 A 15.0-kg block is dragges over a rough, horizontal surface by a 70.0-N force acting at 20 o above the horizontal. The block is displaced 5.0 m and the coefficient of kinetic friction is 0.30. Find the work done by (a) the 70-N force, (b) the normal force, and (c) the force of gravity. (d) What is the energy loss due to friction? W = F d cos Since the wooden cabinet is to be moved at constant velocity, this means that the whole force of 200 N will be used to overcome the force of friction. Thus, the force of friction exerted on the cabinet will be equal to the force applied, which is 200 N.

Conceptual optimization using genetic algorithms for tube in tube structures. SciTech Connect. Pârv, Bianca Roxana; Hulea, Radu; Mojolic, Cristian. 2015-03-10. The purpose of t

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horizontal force of 4.0 N, as shown, with both blocks experiencing equal constant acceleration. (a) Calculate the force that the spring exerts on the 2.0 kg block. (b) Calculate the extension of the spring. The system IS now pulled to the left, as shown below, with both blocks again experiencing equal constant acceleration. 4.0 N 2.0 ko 8.0 kg